Square Matrix

Description:

Given a square matrix of size NN, calculate the absolute difference between the sums of its diagonals. Input The first line contains a single integer N. The next N lines denote the matrix's rows, with each line containing N space-separated integers describing the columns. Output Print the absolute difference between the two sums of the matrix's diagonals as a single integer. Constraints 1<=N<=10 Explanation The primary diagonal is: 11 5 -12 Sum across the primary diagonal: 11 + 5 - 12 = 4 The secondary diagonal is: 4 5 10 Sum across the secondary diagonal: 4 + 5 + 10 = 19 Difference: |4 - 19| = 15 Test Case 1 Input (stdin) 3 11 2 4 4 5 6 10 8 -12 Expected Output 15 Test Case 2 Input (stdin) 3 4 5 5 3 9 6 7 4 6 Expected Output 2

Program :


#include<stdio.h>

#include<stdlib.h>

int main(){

int n,i=0,j=0,d1=0,d2=0,diff;

scanf("%d",&n);

int a[n][n];

for(i=0;i<n;i++){

for(j=0;j<n;j++){

scanf("%d",&a[i][j]);

}}

for(i=0;i<n;i++){

    d1=d1+a[i][i];

    d2=d2+a[i][n-1-i];

}

diff=d1-d2;

if(diff>=0)

printf("%d",diff);

else

printf("%d",-diff);

  return 0;

}