Tweedle-Dee and Tweedle-Dum


Tweedle-Dee and Tweedle-Dum are in a fierce battle playing even-odd nim. This novel game is played on N heaps. Heap i contains ai stones. Like normal nim, Tweedle-Dee and Tweedle-Dum alternate taking a positive number of stones from any single one of the heaps, and the player that can't remove stones loses. However Tweedle-Dee can only take an even number of stones, and Tweedle-Dum can only take an odd number of stones. Alice doesn't want to wait until the end of the game, so she asks you to determine the winner of the game. Remember that Tweedle-Dee and Tweedle-Dum are legendary grandmasters of combinatorial games, so they always play optimally. Input The first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows. The first line of each case consists of an integer N the number of heaps, and a string P the player that starts the game. String P is equal to "Dee" if Tweedle-Dee goes first, or "Dum" if Tweedle-Dum goes first. The second line of each case contains N space separated integers ai the number of stones of the i-th heap. Output For each test case, output a single line containing either "Dee" if Twedle-Dee winns the game or "Dum" otherwise. Constraints 1<=T<=50 1<=N <=50 1<=ai <=50 Test Case 1 Input (stdin) 1 2 Dee 2 2 Expected Output Dum Test Case 2 Input (stdin) 0 Expected Output 0

Program :

import java.util.*;

public class TestClass {

public static void main(String[] args) {

Scanner s=new Scanner(;

       int a=s.nextInt();

       int b=s.nextInt();

       String c=s.nextLine();

       int d=s.nextInt();

       int e=s.nextInt();